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1. What is the concentration of water in pure water?

1 L water weighs 1000 g. Gram molecular wt water = 18 grams

(1000g/L)/(18grams/mole) = 55.5 moles/L or 55.5 molar

2. What is the water concentration of a 1 M NaCl solution?

1 M NaCl --> 2 osmoles. Each osmole displaces approximately 1 mole of water. Therefore the water concentration is (55.5-2)moles/L, or 53.5 molar.

3. Distinguish between... Tonicity of a particular solution is defined by whether steady-state cell volumes change when they are placed in the solution. Osmolality is determined by the number of particles, i.e. ions or molecules, in solution. An "isotonic" solution is one in which cells neither swell nor shrink in the steady state. An "isosmotic" solution (with respect to plasma) is one that has the same osmolality as plasma. The tonicity of a solution depends only on the osmolality of impermeant solutes, whereas the osmolality depends on the concentrations of all solutes. A solution containing 300 mOsm/kg water of urea is isosmotic with plasma, because both have the same osmolality, but it is not isotonic because urea permeates cell membranes easily. Cells placed in a 300 mOsm/kg urea solution will swell as urea and water enter.

4. The edema of congestive heart failure... The central venous pressure is the pressure in the right atrium and thoracic venae cavae. Heart failure can be defined as any abnormality in the pumping action of the heart that reduces its ability to perform external work. Central venous pressure rises as cardiac output declines. The mean arterial blood pressure may stay normal because of compensatory reflexes (homeostatic control), and only decline in the late stages of heart failure. Applying the Starling concept of capillary filtration and reabsorption of fluid, normal arterial pressure and increased venous pressure will decrease reabsorption of fluid at the venous ends of capillaries and hence cause edema.

5. A 70 kg male has a body fluid osmolality... This question was drawn from Berne and Levy, 3rd Ed., pp 756ff. Addition of 290 mMoles of NaCl to the ECF adds 580 mOsm to the ECF. We assume NaCl is restricted to the ECF--i.e. does not cross cell membranes. The osmolality of the ECF will increase, which will cause net water flow from the ICF to the ECF. The flow of water increases osmolality of the ICF. Net water flux ceases when the ECF and ICF have the same effective osmolality.

 

 

 

Calculations:

Initial conditions:

Initial total body water (TBW): 70 kg x 0.6 = 42 kg or 42 L waterInitial ICV volume: 42 x 2/3 = 28 L

Initial ECF volume: 42 x 1/3 = 14 L

Initial total body osmoles: 42 kg x 290 mOsm/kg = 12180 mOsm

Initial ICF osmoles: 28 kg x 290 mOsm/kg = 8120 mOsm

Initial ECF osmoles: 14 kg x 290 mOsm/kg = 4060 mOsm

 

Final conditions:

 

Final osmolality = (new total body osmoles)/(TBW) (12180 mOsm + 580 mOsm)/(42kg water) = 303.8 mOsm/kg water

 

Final ICF volume = ICF osmoles/(new osmolality)

8120 mOsm/(303.8 mOsm/kg water) = 26.7 kg or 26.7 L

 

Final ECF volume = TBW - ICF = 42 - 26.7 = 15.3 L

 

(Could also have been calculated as follows:)

 

Final ECF volume = (new ECF osmoles)/(new osmolality)

(4060mOsm + 580mOsm)/(303.8 mOsm/kg water)

4640/303.8 = 15.3 kg water or 15.3 L

 

Note that addition of NaCl to the ECF has altered the fractions of the TBW contained in the ECF and ICF. The two compartiments no longer contain 1/3 and 2/3 of the TBW.

 

 

6. A 70 kg male has a body fluid osmolality... This is also taken from examples in Berne and Levy, 3rd Ed. Addition of isotonic saline to the ECF does not change the effective osmolality of the ECF. There is, therefore, no driving force for net water movement. The two liters of saline remains in the ECF. The initial conditions are just as calculated for question 5. The final conditions are:

Osmolality of TBW, ECF, ICF unchanged.

Final ECF volume = 14 L + 2 L = 16 LFinal ICF volume = unchanged.

 

7. A patient on the renal ward...Initial conditions:

Initial TBW = 100 kg x .6 = 60 kg or 60 L water

Initial ICF volume = 100 kg x 0.4 = 40 kg or 40 L water

Initial ECF volume = 100 kg x 0.2 = 20 kg or 20 L water

 

Initial Total body osmoles = 60 kg x 290 mOsm/kg = 17400 mOsm

Initial ICF osmoles = 40 kg x 290 mOsm/kg = 11600 mOsm

Initial ECF osmoles = 20 kg x 290 mOsm/kg = 5800 mOsm

 

Final conditions:

Question indicates water absorbed but not excreted. Water will be added to ECF, then equilibration of water between ECF and ICF will take place. Assume solutes do not move between compartments.Final TBW = 60 L + 5 L = 65 LNew osmolality = 17400 mOsm/65 kg water = 267.7 mOsm/kg water in ECF and ICF

ECF Volume = (ECF osmoles)/(new ECF osmolality)

11600 mOsm/(267.7 mOsm/kg water) = 43.3 kg or 43.3 L

ICF Volume = (ICF osmoles)/(new ICF osmolality)

5800 mOsm/(267.7 mOsm/kg water) = 21.7 kg or 21.7 L

As a check, note that 21.7L + 43.3L = 65 L Note also, that the new water is proportioned in the same 1/3, 2/3 ratio as existed originally, since the ratio of milliosmoles is 1/3, 2/3 and does not change when pure water is added.

8. In the patient in 7... The new plasma osmolality would be the same as the osmolality of the other fluids, 267.7 mOsm/kg water.

 

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Copyright 1999, Joe Patlak, Department of Physiology, University of Vermont.
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Last updated: November 01, 2000.